dada la funcion x(t) {    t          (0≤t≤Π/2)
                                      
                                        Π/2       (Π/2≤t≤&Pi

                                       Π-t/2     (Π≤t≤2&Pi

con periodo 2Π aplicar x(2t-&Pi, si es posible subir las imagenes

DESAROLLO:

1)

X(2T-&Pi= { 2T-Π                         0 ≤ 2T-Π≤Π/2
                      Π/2                          Π/2≤ 2T-Π≤Π
                      Π-[(2T-&Pi/2]         Π ≤2T- Π≤2Π

2)

X(2T-&Pi= { 2T-Π                         Π ≤ 2T≤3Π/2
                      Π/2                          3Π/2≤ 2T≤2Π
                      Π-T+Π/2                 2Π ≤2T≤3Π

3)

X(2T-&Pi= { 2T-Π                         Π/2 ≤ T≤3Π/4
                      Π/2                          3Π/4≤ T≤Π
                      3Π/2 - T                  Π ≤T≤3Π/2

Tags: aplicacion